Re: definite integration of 1/a
- To: mathgroup at smc.vnet.net
- Subject: [mg86398] Re: definite integration of 1/a
- From: "Chris Chiasson" <chris at chiasson.name>
- Date: Mon, 10 Mar 2008 02:05:08 -0500 (EST)
- References: <acbec1a40803091930w2e684027l4c0f34d1ad96d2c1@mail.gmail.com>
I meant that I was expecting Log@a On Sun, Mar 9, 2008 at 9:30 PM, Chris Chiasson <chris at chiasson.name> wrote: > In[1]:= > Integrate[1/a,{a,1,ablah},Assumptions\[RuleDelayed]ablah>0] > > Out[1]= > \!\(If[ablah > 1, Log[ablah], > Integrate[1\/a, {a, 1, ablah}, > Assumptions \[Rule] ablah \[LessEqual] 1]]\) > > I was expecting 1/a. Is there something I can do to get that? Thank you. > > -- > http://chris.chiasson.name/ -- http://chris.chiasson.name/
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