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Re: Re: changing style of vertices for ShowGraph with Combinatorica


Lookup"IntroductiontoGraphDrawing"inthedocumentati=
on(at
"tutorial/GraphDrawingIntroduction").Attheendoftheint=
roductory
remarks(onthefirstpageofthetutorial)itsays,r=
egarding
GraphPlot,GraphPlot3D,LayeredGraphPlot,andTreePlot,that

"Inthesefunctions,agraphisrepresentedeitherbya=
listofrules
oftheform{vi->vj,=85},whereviandvjarevert=
ices,orbythe
adjacencymatrixofthegraph.GraphsintheCombinatorica=
package
formatarealsosupported."


On9Mar2008,at09:59,MurrayEisenbergwrote:

>Anotherobservation:it'ssurprisingthatGraphPlot[Cycle=
[3],...]
>works
>atall!The"MoreInformation"onthereferencepag=
eforGraphPlot
>does
>notsayanythingwhatsoevertoindicatethattheargum=
enttoGraphPlot
>canbeaGraph[...]objectsuchasisprovidedby=
Combinatorica!
>


Pleaseaccesstheattachedhyperlinkforanimportantelec=
troniccommunicationsdisclaimer:http://www.lse.ac.uk/collections/s=
ecretariat/legal/disclaimer.htm


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