[Date Index] [Thread Index] [Author Index]

Re: Evaluation details

• To: mathgroup at smc.vnet.net
• Subject: [mg86758] Re: Evaluation details
• From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
• Date: Thu, 20 Mar 2008 02:55:04 -0500 (EST)
• Organization: Uni Leipzig
• References: <frqpsf$57r$1@smc.vnet.net>
• Reply-to: kuska at informatik.uni-leipzig.de

Hi,

but when x has no value, than x+1 try to evaluate x but find
nothing and it try it on and on ..

x=4;
x=x+1

work as expected.

Regards
   Jens


Mumbo Jumbo wrote:
> Hello,
> 
> I am quite puzzled why a Mathematica statement
> x=x+1;
> causes infinite recursion. Since the ducumentation states that the lhs of
> this statement is not evaluated, it seems to me that the evaluation of the
> rhs should not lead to recursive evaluation.
> TIA, Yuri.
> 
>