MathGroup Archive 2008

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Evaluation details


Hi,

but when x has no value, than x+1 try to evaluate x but find
nothing and it try it on and on ..

x=4;
x=x+1

work as expected.

Regards
   Jens


Mumbo Jumbo wrote:
> Hello,
> 
> I am quite puzzled why a Mathematica statement
> x=x+1;
> causes infinite recursion. Since the ducumentation states that the lhs of
> this statement is not evaluated, it seems to me that the evaluation of the
> rhs should not lead to recursive evaluation.
> TIA, Yuri.
> 
> 


  • Prev by Date: Re: Creating a function that is a derivative of another function??
  • Next by Date: Ordering function
  • Previous by thread: Re: Evaluation details
  • Next by thread: Re: Evaluation details