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Re: Definite integral

  • To: mathgroup at smc.vnet.net
  • Subject: [mg88471] Re: Definite integral
  • From: Budaoy <yaomengliang at gmail.com>
  • Date: Tue, 6 May 2008 06:39:37 -0400 (EDT)
  • References: <fvmmrd$8ef$1@smc.vnet.net>

On 5=D4=C25=C8=D5, =CF=C2=CE=E76=CA=B117=B7=D6, Miguel <misv... at gmail.com> w=
rote:
> I don't understand Mathematica can't calculate the last definite
> integral. For the first three integrals works fine, but for the last
> one crush. You can see in this paper
>
> http://mathematicaes.googlegroups.com/web/Curves.pdf?gda=7zTXujoAAAA-...
>
> Thanks

What I get is 3/2 + 1/2 (3 - 3 Abs[Cos[t]] Sin[t] Tan[t]) if your
definition is s4[t_] = s2[Pi*3/2] + Integrate[...]. But I think it may
be s4[t_] = s3[Pi*3/2] + Integrate[...], in this case the answer is
9/2+1/2 (3-3 Abs[Cos[t]] Sin[t] Tan[t]). U should add t > Pi*3/2 to
the assumption.


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