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Re: Definite integral

  • To: mathgroup at
  • Subject: [mg88475] Re: [mg88434] Definite integral
  • From: Curtis Osterhoudt <cfo at>
  • Date: Tue, 6 May 2008 06:41:16 -0400 (EDT)
  • Organization: LANL
  • References: <>
  • Reply-to: cfo at

Hi, Miguel, 

   I'm not sure why Mathematica wouldn't do it, but the result of that 
unevaluated integral is (using on Linux x86 -- 32-bit)

Integrate[(3/2)*Sqrt[Sin[2*\[Theta]]^2], {\[Theta], 3*(Pi/2), t}, 
   Assumptions -> Element[t, Reals] && 3*(Pi/2) < \[Theta] < 2*Pi]

-(3/(2*Sign[3*Pi - 2*t])) - (3/2)*Abs[Cos[t]]*Sin[t]*Tan[t]

            Hope that helps!

On Monday 05 May 2008 04:14:05 Miguel wrote:
> I don't understand Mathematica can't calculate the last definite
> integral. For the first three integrals works fine, but for the last
> one crush. You can see in this paper
> Thanks

Curtis Osterhoudt
cfo at
PGP Key ID: 0x4DCA2A10
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