Re: ListDensityPlot with irregular data and InterpolationOrder

*To*: mathgroup at smc.vnet.net*Subject*: [mg88554] Re: ListDensityPlot with irregular data and InterpolationOrder*From*: Bill Rowe <readnews at sbcglobal.net>*Date*: Thu, 8 May 2008 04:14:14 -0400 (EDT)

On 5/7/08 at 7:10 AM, szhorvat at gmail.com (Szabolcs Horv=C3=A1t) wrote: >This is not explicitly documented (or at least I could not find any >mention of it), but from looking at the plots it seems to me that >with ListDensityPlot (and related functions), an InterpolationOrder >higher than 1 only work with data that lies on a regular grid. >So for example the following data cannot be plotted with >InterpolationOrder higher than 1: >data = {#1, #2, Sin[#1] Sin[#2]} & @@@ RandomReal[2 Pi, {100, 2}]; >Is this correct? The array you create above is a regular array and as far as I can see there is no problem with using an InterpolationOrder greater than 1. That is, using your code above to assign values to data ListDensityPlot[data] ListDensityPlot[data,InterpolationOrder->1] ListDensityPlot[data,InterpolationOrder->3] all execute with no error messages. True, all three graphics appear identical. But I believe this is due the functional relationship you created. Do the following data=RandomReal[2 Pi, {5,5}]; then ListDensityPlot[data] ListDensityPlot[data,InterpolationOrder->1] ListDensityPlot[data,InterpolationOrder->3] All three should execute with no error and the images will not be the same due to the different interpolation order.