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Re: Computing n-grams

  • To: mathgroup at smc.vnet.net
  • Subject: [mg88971] Re: [mg88913] Computing n-grams
  • From: "Richard Palmer" <rhpalmer at gmail.com>
  • Date: Thu, 22 May 2008 02:39:47 -0400 (EDT)
  • References: <200805211849.OAA10371@smc.vnet.net>

Try Partition[list,n,1] where list is the list to be partitioned

On 5/21/08, Coleman, Mark <Mark.Coleman at libertymutual.com> wrote:
>
> Greetings,
>
> Imagine one has a list such as {a,b,c,d,e,f,g}. I'm trying to find an
> efficient way in Mathematica to compute the n-grams of the list. That is,
> for
> n=2, the n-grams are all the lists of length 2 consisting of consecutive
> elements, e.g.,
>
> {a,b},{b,c},{c,d},{d,e},...
>
> While for n=3,
>
> {a,b,c},{b,c,d},{c,d,e},..., and so on.
>
> As I understand it, the built-in Mathematica commands such as Subsets or
> Permutations compute all possible list of size n, without regard to the
> order of the list elements.
>
> Thanks,
>
> Mark
>
>
>


-- 
Richard Palmer

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