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RE: Computing n-grams
*To*: mathgroup at smc.vnet.net
*Subject*: [mg89015] RE: [mg88913] Computing n-grams
*From*: "Coleman, Mark" <Mark.Coleman at LibertyMutual.com>
*Date*: Fri, 23 May 2008 03:11:22 -0400 (EDT)
*References*: <200805211849.OAA10371@smc.vnet.net> <DC52E3F2-FD62-4433-8C1A-EB550B8DB818@mimuw.edu.pl>
Thanks to all MathGroup members who so promptly pointed out solutions to
my recent posting regarding n-grams.
I must (sheepishly) confess this is not the first time (nor I am sure
the last) that far more astute Mathematica users than me have pointed me towards
solutions using built-in commands. In the future I shall endeavor to
find questions more worthy of MathGroup users' skills! *smile*
Cheers,
Mark
On 22 May 2008, at 03:49, Coleman, Mark wrote:
> Greetings,
>
> Imagine one has a list such as {a,b,c,d,e,f,g}. I'm trying to find an
> efficient way in Mathematica to compute the n-grams of the list.
> That is, for
> n=2, the n-grams are all the lists of length 2 consisting of
> consecutive elements, e.g.,
>
> {a,b},{b,c},{c,d},{d,e},...
>
> While for n=3,
>
> {a,b,c},{b,c,d},{c,d,e},..., and so on.
>
> As I understand it, the built-in Mathematica commands such as Subsets
> or Permutations compute all possible list of size n, without regard to
> the order of the list elements.
>
> Thanks,
>
> Mark
>
>
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