Re: How to programmatically rewrite (x + y/z) as (xz+ y)/z ?

• To: mathgroup at smc.vnet.net
• Subject: [mg89163] Re: How to programmatically rewrite (x + y/z) as (xz+ y)/z ?
• From: dh <dh at metrohm.ch>
• Date: Wed, 28 May 2008 04:42:54 -0400 (EDT)
• References: <g1gqk6\$1g1\$1@smc.vnet.net>

```
Hi,

Together will do the trick:

Together [(x+y/z)]

hope this helps, Daniel

TuesdayShopping wrote:

> Given "(x + y/z)" as input, how do I get the same expression in the form of "(xz+ y)/z".

>

> Note that the input form may not always have 2 terms. It may be arbitrarily long or may not be in any standard form. It may be like  "x+y", or "x + y + (2*w)/z - p/3 +10", or "c", or  "x/2"   . . . .All that can be assumed about the input is that they are all polynomials bound together with the 5 operators (+, -, *, / and ^), and that whatever the output is, the denominator can be assumed to be not equal to 0.

>

> Thanks a lot.

>

--

Daniel Huber

Metrohm Ltd.

Oberdorfstr. 68

CH-9100 Herisau

Tel. +41 71 353 8585, Fax +41 71 353 8907

E-Mail:<mailto:dh at metrohm.com>

Internet:<http://www.metrohm.com>

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