Re: How to programmatically rewrite (x + y/z) as (xz+ y)/z ?

• To: mathgroup at smc.vnet.net
• Subject: [mg89174] Re: How to programmatically rewrite (x + y/z) as (xz+ y)/z ?
• From: "David Park" <djmpark at comcast.net>
• Date: Wed, 28 May 2008 04:44:56 -0400 (EDT)
• References: <g1gqk6\$1g1\$1@smc.vnet.net>

```With the Presentations package from my web site below (\$50) this is easy.
Just use FactorOut.

Needs["Presentations`Master`"]

x + y/z // FactorOut[1/z]
(y + x z)/z

x + y + (2*w)/z - p/3 + 10 // FactorOut[1/z]
(2 w + 10 z - (p z)/3 + x z + y z)/z

--
David Park
djmpark at comcast.net
http://home.comcast.net/~djmpark/

"TuesdayShopping" <TuesdayShopping at yahoo.com> wrote in message
news:g1gqk6\$1g1\$1 at smc.vnet.net...
> Given "(x + y/z)" as input, how do I get the same expression in the form
> of "(xz+ y)/z".
>
> Note that the input form may not always have 2 terms. It may be
> arbitrarily long or may not be in any standard form. It may be like
> "x+y", or "x + y + (2*w)/z - p/3 +10", or "c", or  "x/2"   . . . .All that
> can be assumed about the input is that they are all polynomials bound
> together with the 5 operators (+, -, *, / and ^), and that whatever the
> output is, the denominator can be assumed to be not equal to 0.
>
> Thanks a lot.
>

```

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