       Re: simplify polynomial

• To: mathgroup at smc.vnet.net
• Subject: [mg89196] Re: simplify polynomial
• From: dh <dh at metrohm.ch>
• Date: Thu, 29 May 2008 07:02:46 -0400 (EDT)
• References: <g1j6im\$qop\$1@smc.vnet.net>

```
Hi,

do not use funny characters like: Î», I replace it b:x.

It is not very clear to me what you mean by incomplete factorization.

Well, a polynomial (with variable x) can always be factorized, using its

zeros.In your case of a third degree poly: c0 (x-c1)(x-c2)(x-c3). If you

want to split an additional summand, you could eliminate e.g. x1 and add

the summand: c0 x(x-c2)(x-c3)+c4. The ci you can get using SolveAlways:

SolveAlways[yourPoly==c0 x(x-c2)(x-c3)+c4,x]

will give you the ci.

hope this helps, Daniel

vmarian wrote:

> I want to simplify a polynomial by factorizing the most of the  terms as possible(that means a product of terms plus a small other

> number of terms). I didn't find how to do such incomplete factorization. Is there a command to do it. Factor works only for complete factorizations.

>

> \!\(Simplify[2 - Î» - Î»\^2 - 3\ hmb\ \((\(-2\) + Î» +

>       Î»\^2)\) + hmb\^3\ \((5 - 12\ Î» + 4\ Î»\^2)\) + hmb\^2\ \((6 - 3\ Î» -

>       8\ Î»\^2 + 2\ Î»\^3)\)]\)

>

> Thank you.

>

--

Daniel Huber

Metrohm Ltd.

Oberdorfstr. 68

CH-9100 Herisau

Tel. +41 71 353 8585, Fax +41 71 353 8907

E-Mail:<mailto:dh at metrohm.com>

Internet:<http://www.metrohm.com>

```

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