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Re: Exporting the output of GraphPlot

  • To: mathgroup at
  • Subject: [mg89221] Re: [mg89188] Exporting the output of GraphPlot
  • From: "W_Craig Carter" <ccarter at>
  • Date: Fri, 30 May 2008 02:55:07 -0400 (EDT)
  • References: <>

Hello Abhishek,
Here is an example of a way to do this, it is not very general:

admat = Table[RandomInteger[], {12}, {12}];
gc = GraphPlot[admat]

FullForm[gc] (*Reveals the structure of the graphics, the first
argument of the GraphicsComplex is the
vertex list*)

pts = gc[[1, 1, 1, All]] (*extract the points*)

On Thu, May 29, 2008 at 7:01 AM,  <meghamani at> wrote:
> Hi,
>     Is there a way to get the output of GraphPlot/GraphPlot3D as
> (x,y,z) coordinates? I want to use the output as the basis for
> ContourPlot3D.
>    The input is a 3 connected graph - it is distorted flat lattice
> with bumps. The 'spring' algorithms in GraphPlot3D give a pretty
> decent representation. But I really need a contour plot on top of this
> 'mesh'. Any ideas?
> Thanks,
> Abhishek

W. Craig Carter

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