Re: Exporting the output of GraphPlot

*To*: mathgroup at smc.vnet.net*Subject*: [mg89221] Re: [mg89188] Exporting the output of GraphPlot*From*: "W_Craig Carter" <ccarter at mit.edu>*Date*: Fri, 30 May 2008 02:55:07 -0400 (EDT)*References*: <200805291101.HAA27299@smc.vnet.net>

Hello Abhishek, Here is an example of a way to do this, it is not very general: admat = Table[RandomInteger[], {12}, {12}]; gc = GraphPlot[admat] FullForm[gc] (*Reveals the structure of the graphics, the first argument of the GraphicsComplex is the vertex list*) pts = gc[[1, 1, 1, All]] (*extract the points*) On Thu, May 29, 2008 at 7:01 AM, <meghamani at gmail.com> wrote: > Hi, > Is there a way to get the output of GraphPlot/GraphPlot3D as > (x,y,z) coordinates? I want to use the output as the basis for > ContourPlot3D. > The input is a 3 connected graph - it is distorted flat lattice > with bumps. The 'spring' algorithms in GraphPlot3D give a pretty > decent representation. But I really need a contour plot on top of this > 'mesh'. Any ideas? > > Thanks, > Abhishek > > -- W. Craig Carter

**References**:**Exporting the output of GraphPlot***From:*meghamani@gmail.com