Fourier Transform
- To: mathgroup at smc.vnet.net
- Subject: [mg93476] Fourier Transform
- From: Nikolaus Rath <Nikolaus at rath.org>
- Date: Mon, 10 Nov 2008 03:31:28 -0500 (EST)
Hello, Consider the following expression: expr = (c^2 Sqrt[2 \[Pi]] DiracDelta[ky + sy] DiracDelta[sz])/(-c^2 sx^2 - c^2 sy^2 - c^2 sz^2 + \[Omega]^2); $Assumptions = {{x, y, z} \[Element] Reals}; InverseFourierTransform[expr, {sx, sy, sz}, {x, y, z}] // Timing Integrate[ 1/Sqrt[2 \[Pi]] Exp[-I sx x] Exp[-I sy y] Exp[-I sz z] expr, {sx, -\[Infinity], \[Infinity]}, {sy, -\[Infinity], \ \[Infinity]}, {sz, -\[Infinity], \[Infinity]}] // Timing On my system with Mathematica 6, the explicit integration takes 3 times as long as the InverseFourierTransform and also gives several additional required assumptions for the same result (e.g. Im[-ky^2 + \[Omega]^2/c^2] != 0 || Re[-ky^2 + \[Omega]^2/c^2] <= 0). How is this possible? Is Mathematica using some special tricks when evaluating the InverseFourierTransform? Best, -Nikolaus -- =C2=BBIt is not worth an intelligent man's time to be in the majority. By definition, there are already enough people to do that.=C2=AB -J.H. Hardy PGP fingerprint: 5B93 61F8 4EA2 E279 ABF6 02CF A9AD B7F8 AE4E 425C