Re: Re: Hypergeometric2F1
- To: mathgroup at smc.vnet.net
- Subject: [mg93197] Re: [mg93183] Re: Hypergeometric2F1
- From: Andrzej Kozlowski <akoz at mimuw.edu.pl>
- Date: Fri, 31 Oct 2008 03:03:51 -0500 (EST)
- References: <200810300702.CAA00649@smc.vnet.net>
On 30 Oct 2008, at 16:02, Bill Rowe wrote:
> On 10/29/08 at 5:50 AM, DWCantrell at sigmaxi.net (David W. Cantrell)
> wrote:
>
>> Artur <grafix at csl.pl> wrote:
>>> Dear Mathematica Gurus! Who know which Mathematica procedure to use
>>> to find such a,b,c that
>>> ArcCosh[2]/ArcCosh[2-x]==Hypergeometric2F1[a,b,c,x] for
>>> {x,-Infinity,1}
>
>> It seems that you are wanting to determine a,b,c such that
>
>> ArcCosh[2]/ArcCosh[2-x]==Hypergeometric2F1[a,b,c,x]
>
>> would be an identity for x < 1. But that is not possible. What made
>> you think it would be possible?
>
> Given
>
> In[17]:= Hypergeometric2F1[a, b, c, 0]
>
> Out[17]= 1
>
> It appears there are infinitely many solutions. Is the result
> returned by Mathematica for Hypergeometric2F1[a,b,c,x] incorrect
> when x = 0? What am I missing here?
>
It's a matter of mind reading ;-)
The questioner "obviously meant" "for all x<1".
Andrzej Kozlowski
- References:
- Re: Hypergeometric2F1
- From: Bill Rowe <readnews@sbcglobal.net>
- Re: Hypergeometric2F1