Mathematica 9 is now available
Services & Resources / Wolfram Forums / MathGroup Archive
-----

MathGroup Archive 2008

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Re: Hypergeometric2F1

  • To: mathgroup at smc.vnet.net
  • Subject: [mg93227] Re: [mg93183] Re: Hypergeometric2F1
  • From: Artur <grafix at csl.pl>
  • Date: Fri, 31 Oct 2008 03:09:18 -0500 (EST)
  • References: <200810300702.CAA00649@smc.vnet.net>
  • Reply-to: grafix at csl.pl

Result is correct

Hypergeometric2F1[a,b,c,0]=1

You can understand this when you plot

Plot[{Hypergeometric2F1[1/2,1/3,1/4,x],Hypergeometric2F1[1/5,1/3,1/4,x],
Hypergeometric2F1[1/2,1/3,1/5,x]},{x,-1,1}]

Best wishes
Artur



Bill Rowe pisze:
> On 10/29/08 at 5:50 AM, DWCantrell at sigmaxi.net (David W. Cantrell)
> wrote:
>
>   
>> Artur <grafix at csl.pl> wrote:
>>     
>>> Dear Mathematica Gurus! Who know which Mathematica procedure to use
>>> to find such a,b,c that
>>> ArcCosh[2]/ArcCosh[2-x]==Hypergeometric2F1[a,b,c,x] for
>>> {x,-Infinity,1}
>>>       
>
>   
>> It seems that you are wanting to determine a,b,c such that
>>     
>
>   
>> ArcCosh[2]/ArcCosh[2-x]==Hypergeometric2F1[a,b,c,x]
>>     
>
>   
>> would be an identity for x < 1. But that is not possible. What made
>> you think it would be possible?
>>     
>
> Given
>
> In[17]:= Hypergeometric2F1[a, b, c, 0]
>
> Out[17]= 1
>
> It appears there are infinitely many solutions. Is the result
> returned by Mathematica for Hypergeometric2F1[a,b,c,x] incorrect
> when x = 0? What am I missing here?
>
>
> __________ Information from ESET NOD32 Antivirus, version of virus signature database 3567 (20081029) __________
>
> The message was checked by ESET NOD32 Antivirus.
>
> http://www.eset.com
>
>
>
>   


  • Prev by Date: Graph by Date
  • Next by Date: Re: Re: Re: Is there a way to make Mathematica commands and functions
  • Previous by thread: Re: Re: Hypergeometric2F1
  • Next by thread: Re: Hypergeometric2F1