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Re: Integrate with parameter


Nico wrote:

 > I can't find out how I can calculate this integral

 > I(x) = \int_{-\infty}^{+\infty} Exp(-a*v^2)*Erf(v + A(x)) dv

*snip*

Do you mean, in proper *Mathematica* syntax,

   Integrate[Exp[(-a)*v^2]*Erf[v + A[x]], {v, -Infinity, Infinity}]

Regards,
-- Jean-Marc



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