Re: Integrate with parameter
- To: mathgroup at smc.vnet.net
- Subject: [mg91657] Re: Integrate with parameter
- From: Jean-Marc Gulliet <jeanmarc.gulliet at gmail.com>
- Date: Tue, 2 Sep 2008 07:17:51 -0400 (EDT)
- Organization: The Open University, Milton Keynes, UK
Nico wrote: > I can't find out how I can calculate this integral > I(x) = \int_{-\infty}^{+\infty} Exp(-a*v^2)*Erf(v + A(x)) dv *snip* Do you mean, in proper *Mathematica* syntax, Integrate[Exp[(-a)*v^2]*Erf[v + A[x]], {v, -Infinity, Infinity}] Regards, -- Jean-Marc