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MathGroup Archive 2008

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Re: Integrate with parameter

  • To: mathgroup at smc.vnet.net
  • Subject: [mg91657] Re: Integrate with parameter
  • From: Jean-Marc Gulliet <jeanmarc.gulliet at gmail.com>
  • Date: Tue, 2 Sep 2008 07:17:51 -0400 (EDT)
  • Organization: The Open University, Milton Keynes, UK

Nico wrote:

 > I can't find out how I can calculate this integral

 > I(x) = \int_{-\infty}^{+\infty} Exp(-a*v^2)*Erf(v + A(x)) dv

*snip*

Do you mean, in proper *Mathematica* syntax,

   Integrate[Exp[(-a)*v^2]*Erf[v + A[x]], {v, -Infinity, Infinity}]

Regards,
-- Jean-Marc



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