Re: Integrate with parameter

*To*: mathgroup at smc.vnet.net*Subject*: [mg91657] Re: Integrate with parameter*From*: Jean-Marc Gulliet <jeanmarc.gulliet at gmail.com>*Date*: Tue, 2 Sep 2008 07:17:51 -0400 (EDT)*Organization*: The Open University, Milton Keynes, UK

Nico wrote: > I can't find out how I can calculate this integral > I(x) = \int_{-\infty}^{+\infty} Exp(-a*v^2)*Erf(v + A(x)) dv *snip* Do you mean, in proper *Mathematica* syntax, Integrate[Exp[(-a)*v^2]*Erf[v + A[x]], {v, -Infinity, Infinity}] Regards, -- Jean-Marc