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Re: Trying to speed up a function

  • To: mathgroup at
  • Subject: [mg91844] Re: Trying to speed up a function
  • From: dh <dh at>
  • Date: Wed, 10 Sep 2008 05:07:32 -0400 (EDT)
  • References: <g9t6jq$j66$>

Hi Abhishek,

no mistery here. By definition Table[expr,{n}] completely evaluates expr 

n times. Therefore, it is a good idea to take out redundant 

calculations. Note also that Table has the attribute "HoldAll" and does 

therefore not evaluate its arguments.


gophergoon at wrote:

> Say I have a previously defined matrix 'vecs' and I want to calculate

> certain sums of columns. I find it easier to write in terms of the

> Transpose but it seems that when I put Transpose[vecs] in the

> definition of a table, mathematica evaluates the transpose over and

> over to get at every element of the matrix. Which takes much longer

> than doing it in 2 steps (2nd method). I only found this out by trial

> and error so I am curious about the explanation for this behaviour and

> how to avoid it in general.


> BTW I am aware that the expression can be written in 1 line without

> using Transpose also, but I'd still like to know how to tell that if a

> sub-expression in a function is going to be evaluated repeatedly.

> Thanks,

> Abhishek


> In[15]:= Dimensions[vecs]


> Out[15]= {1620, 1620}


> In[23]:= Table[Total[Transpose[vecs][[n]][[811 ;; 1620]]], {n, 1,

> 1620}]; // Timing


> Out[23]= {27.844, Null}


> In[24]:= vecst = Transpose[vecs];

> Table[Total[vecst[[n]][[811 ;; 1620]]], {n, 1, 1620}]; // Timing


> Out[25]= {0.016, Null}



Daniel Huber

Metrohm Ltd.

Oberdorfstr. 68

CH-9100 Herisau

Tel. +41 71 353 8585, Fax +41 71 353 8907

E-Mail:<mailto:dh at>


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