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Re: integration frustration

  • To: mathgroup at smc.vnet.net
  • Subject: [mg91927] Re: integration frustration
  • From: "David Park" <djmpark at comcast.net>
  • Date: Sat, 13 Sep 2008 05:54:04 -0400 (EDT)
  • References: <gadcke$riv$1@smc.vnet.net>

Mathematica won't perform the integration unless f is defined. However, I 
think your statement is true provided f is a monotonically increasing 
function.

-- 
David Park
djmpark at comcast.net
http://home.comcast.net/~djmpark/


"Replacedwings" <cabaret_voltaire at hotmail.com> wrote in message 
news:gadcke$riv$1 at smc.vnet.net...
> Dear All,
>
> I have a question about a particular integral:
>
>
> i[r]= Integrate[(L-z)(f[Sqrt[z^2+r^2]] -f[z]),{z,0,L}]
>
>
> Assumptions->f[0]==0, f[r]>0 if r>0.
>
> Is i[r]>=0 for all r?
>
> Any Ideas?
>
> Help!
>
> TIA,
>
> Chris
> 



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