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Re: How to remove all cycles

  • To: mathgroup at smc.vnet.net
  • Subject: [mg98319] Re: How to remove all cycles
  • From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
  • Date: Mon, 6 Apr 2009 04:59:48 -0400 (EDT)
  • References: <gr6c4a$poi$1@smc.vnet.net>

Hi,

With[{n = 4},
  B = Table[Prime[2*j*k], {j, 1, 2}, {k, 1, 2^n}]
  ]

A=Flatten[Transpose[B]]

?

Regards
   Jens

buts wrote:
> Hello, 
> I want to write the following code using functional
> programming, i.e. to remove all Do's.
> There are two arrays: 
> 
> A[[i]], i=1,...,2^(n+1)
> B[[j,k]], j=1,2;  k=1,...,2^n.
> 
> I need to assign B to A setting the first bit of the index i
> to be the index j. Explicitly
> 
> Do[Do[A[[ j + BitShiftLeft[k-1,1] ]]= B[[j,k]],
> {j,1,2}],{k,1,2^n}]
> 
> I need to do it for multi-dimensional large arrays.
> Is it possible to write it without Do's ?
> 
> Thanks.
> 


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