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Re: Plotting a x,y,z function

That's not Mathematica syntax... it's YOUR math problem.

If you don't know what r is about, how could we possibly know?

That said, it's POSSIBLE you want r^2 to be x^2 + y^2.


On Wed, 15 Apr 2009 03:59:44 -0500, chem_chick  
<raeanne.napoleon at> wrote:

> I needed help plotting the following function:
> f[x_,y_,z_] = (x^2+y^2+z^2) e^-(r^2/2)
> ContourPlot3D[(x^2 + y^2 - z^2) Exp[-r^2/2], {x, -10, 10}, {y, -10,
>   10}, {z, -10, 10}]
> does not work because it doesn't understand what r (radius) is....what
> is the keyword/whatever for radius?  Or do I have to define r in terms
> of x,y,z somehow?!   Help with syntax will be great!
> Thanks!

DrMajorBob at

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