Services & Resources / Wolfram Forums / MathGroup Archive
-----

MathGroup Archive 2009

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Plotting a x,y,z function

  • To: mathgroup at smc.vnet.net
  • Subject: [mg98710] Re: Plotting a x,y,z function
  • From: sean_incali at yahoo.com
  • Date: Thu, 16 Apr 2009 04:19:25 -0400 (EDT)
  • References: <gs47lm$7p3$1@smc.vnet.net>

You have to provide a value for r.

ContourPlot3D[(x^2 + y^2 - z^2) Exp[-r^2/2 /. r -> 1], {x, -10,
  10}, {y, -10, 10}, {z, -10, 10}]

But varying r doesn't seem to do much

Manipulate[
 ContourPlot3D[(x^2 + y^2 - z^2) Exp[-r^2/2], {x, -10, 10}, {y, -10,
   10}, {z, -10, 10}, Mesh -> False], {r, 1, 10}]


On Apr 15, 1:59 am, chem_chick <raeanne.napol... at gmail.com> wrote:
> I needed help plotting the following function:
>
> f[x_,y_,z_] = (x^2+y^2+z^2) e^-(r^2/2)
>
> ContourPlot3D[(x^2 + y^2 - z^2) Exp[-r^2/2], {x, -10, 10}, {y, -10,
>   10}, {z, -10, 10}]
>
> does not work because it doesn't understand what r (radius) is....what
> is the keyword/whatever for radius?  Or do I have to define r in terms
> of x,y,z somehow?!   Help with syntax will be great!
>
> Thanks!



  • Prev by Date: Re: Plotting a x,y,z function
  • Next by Date: Re: Simplify
  • Previous by thread: Re: Plotting a x,y,z function
  • Next by thread: Re: Plotting a x,y,z function