• To: mathgroup at smc.vnet.net
• From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
• Date: Fri, 17 Apr 2009 04:26:54 -0400 (EDT)
• References: <gs6pfe\$h1o\$1@smc.vnet.net>

```Hi,

may be you should stop to use N as a variable because
N[] is the function to convert a analytic number into
a floating point number.

Regards
Jens

olfa wrote:
> Hi Mathematica community,
> I have to solve this system:
> Reduce[{Element[{i, j}, Integers], i <= iP, j >= jP,
>   1*j + 1*i == 1*jP + 1*iP,
>   Reduce[{Element[{N, iP}, Integers], Not[(iP < N)],
>     Exists[{iPP}, (iPP < N) && iP == iPP + 1]}]}, {iP, jP},
>  Backsubstitution -> True]
>
> the output should be:( i | j | N | iP) are Integers && i <= N && iP ==
> N &&
>  jP == i + j - N
> but mathematica gave me this output:
> (C[1] | C[2] | C[3] | C[4]) are Integers && C[1] >= 0 &&
>  C[2] >= 0 && C[3] >= 0 && C[4] >= 0 && i == C[1] - C[2] - C[3] &&
>  iP == C[1] - C[2] + C[4] && N == C[1] - C[2] + C[4] &&
>  jP == j - C[3] - C[4]
>
> which is not understandable at all! and I dont want the output to be
> like that.
>
> I have observed that when I remove i from Element[{i, j}, Integers]
> mathematica give me the output I want and which is :iP == N &&  jP ==
> i + j - N
>
> So how can I have this same output without removing i from Element[{i,
> j}, Integers]?
>
> Thank you very much in advance.
>

```

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