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Re: factor out a term to cancel in a fraction

• To: mathgroup at smc.vnet.net
• Subject: [mg98835] Re: [mg98818] factor out a term to cancel in a fraction
• From: Andrzej Kozlowski <akoz at mimuw.edu.pl>
• Date: Mon, 20 Apr 2009 05:39:37 -0400 (EDT)
• References: <200904200531.BAA00876@smc.vnet.net>

Factor[(e0*s[t]*k1*k2)/(s[t]*k1 + k1*Km)]
(e0*k2*s[t])/(Km + s[t])

or

Cancel[(e0*s[t]*k1*k2)/(s[t]*k1 + k1*Km)]
(e0*k2*s[t])/(Km + s[t])

Difficult ? Give an example of "easy".

And by the way, where did you get the idea that Assuming does anything  
at all with Collect?

Andrzej Kozlowski



On 20 Apr 2009, at 14:31, sean_incali at yahoo.com wrote:

> Hello group.
>
> I'm trying to do a little algebra which i can do in my head using
> Mathematica.  Why? Well, it's neater.
>
> Consider the following.
>
>
> p'[t] == (e0 s[t] k1 k2 )/ (s[t] k1 + k1 Km)
>
> Factor out k1 and cancel it to simplify the expression. Why is this so
> difficult to accomplish in mathematica?  Following does nothing.
>
> p'[t] == (e0 s[t] k1 k2 )/ (s[t] k1 + k1 Km) //
> Assuming[k1 > 0, {Collect[#, k1]}] &
>
>
> Thanks for any info.
>
> Sean
>
>

• References:
  • factor out a term to cancel in a fraction
    • From: sean_incali@yahoo.com