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Re: factor out a term to cancel in a fraction


Hi,

eqn = p'[t] == (e0 s[t] k1 k2)/(s[t] k1 + k1 Km);

and

eqn /. a_ == b_ :> a == Cancel[b]

or

Cancel[eqn]

or

Simplify[eqn]

or

FullSimplify[eqn]

or

eqn /. a_*k1 + b_*k1 :> (a + b)*k1

will do it and it seems difficult to hinder Mathematica
to cancel k1.

Regards
   Jens





sean_incali at yahoo.com wrote:
> Hello group.
> 
> I'm trying to do a little algebra which i can do in my head using
> Mathematica.  Why? Well, it's neater.
> 
> Consider the following.
> 
> 
> p'[t] == (e0 s[t] k1 k2 )/ (s[t] k1 + k1 Km)
> 
> Factor out k1 and cancel it to simplify the expression. Why is this so
> difficult to accomplish in mathematica?  Following does nothing.
> 
> p'[t] == (e0 s[t] k1 k2 )/ (s[t] k1 + k1 Km) //
>  Assuming[k1 > 0, {Collect[#, k1]}] &
> 
> 
> Thanks for any info.
> 
> Sean
> 
> 


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