ContourPlot, equation and R.H. side of equation_Plotting problem

*To*: mathgroup at smc.vnet.net*Subject*: [mg99051] ContourPlot, equation and R.H. side of equation_Plotting problem*From*: Bill <WDWNORWALK at aol.com>*Date*: Sat, 25 Apr 2009 04:50:35 -0400 (EDT)

Hi: 1a.) When I assign 3 x^2 + 6 y^2 == 6 to eqn1, in Mathematica like this: eqn1=3 x^2 + 6 y^2 == 6; I can't get ContourPlot to plot eqn1 using this code: ContourPlot[eqn1, {x, -2, 2}, {y, -2, 2}, Axes -> True] 1b.) If I assign the equation like this without the constant on the R.H. side in eqn2, ContourPlot will plot the equation as expected, using the following syntax: eqn2=3 x^2 + 6 y^2; ContourPlot[eqn2 == 6, {x, -2, 2}, {y, -2, 2}, Axes -> True] Question: How can I get method 1a to work? Could you please give me code for this? Thanks, Bill PS. I'm using Mathematica 6.0.1 w/ Win XP on a PC.