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Re: A Question about Combinatorica

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  • Subject: [mg102655] Re: A Question about Combinatorica
  • From: Helen Read <hpr at>
  • Date: Sun, 23 Aug 2009 05:33:21 -0400 (EDT)
  • References: <> <h6o73j$fsa$>
  • Reply-to: HPR <read at>

Tomas Garza wrote:
> Number of combinations of n objects taken in sets of k, is that what you mean?
> The answer to that is n!/k! (n-k)!
> The actual combinations carry in Mathematica the strange name of
> KSubsets, and in order to calculate them you must FIRST call the
> Combinatorica package: thus
> <<Combinatorica`
> KSubsets[{"A","B","C","D"},3]
> {{A,B,C},{A,B,D},{A,C,D},{B,C,D}}

There is no need to load a package for this. Use the built-in function 

Subsets[{"A", "B", "C", "D"}, {3}]

Also useful are the built-in functions Tuples and Permutations.

Helen Read
University of Vermont

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