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Re: A simpl(e)ification

  • To: mathgroup at smc.vnet.net
  • Subject: [mg105779] Re: A simpl(e)ification
  • From: DC <b.gatessucks at gmail.com>
  • Date: Fri, 18 Dec 2009 06:24:20 -0500 (EST)
  • References: <hgd7qr$bkk$1@smc.vnet.net>

You might try

In[3]:= ComplexExpand[Im[E^(-2 I a) 1/b], TargetFunctions -> {Re, Im}]

Out[3]= -(Sin[2 a]/b)

-Francesco

On 12/17/2009 12:22 PM, Pianiel wrote:
> Dear All,
>
> With Mathematica 7.0.1, the following expression;
>
> Simplify[  Im[E^(-2 I a) b],  Assumptions ->  Element[a, Reals]&&
> Element[b, Reals]]
>
> gives
>
> -b Sin[2 a]
>
> But:
>
> Simplify[  Im[E^(-2 I a) 1/b],  Assumptions ->  Element[a, Reals]&&
> Element[b, Reals]]
>
> gives
>
> Im[E^(-2 I a)/b]
>
> So we see that the Im[] is not simplified. Why?
>
> Any idea how to help mathematica to handle the simplification shown in
> the second example. It seems to be so similar to the first kind...
>
> Thanks in advance
>
> Pianiel
>


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