Re: reverse the order of replacements in a list of rules
- To: mathgroup at smc.vnet.net
- Subject: [mg105966] Re: [mg105954] reverse the order of replacements in a list of rules
- From: "David Park" <djmpark at comcast.net>
- Date: Mon, 28 Dec 2009 04:57:16 -0500 (EST)
- References: <31658378.1261900384846.JavaMail.root@n11>
Map (/@) Reverse onto your list of rules.
toyrule = {k1 k2 -> a, k3 k4 k5 -> b, k4 k6 k7 -> c,
k8 k9/k10 + k11 -> d};
Reverse /@ toyrule
{a -> k1 k2, b -> k3 k4 k5, c -> k4 k6 k7, d -> k11 + (k8 k9)/k10}
David Park
djmpark at comcast.net
http://home.comcast.net/~djmpark/
From: sean [mailto:sean_incali at yahoo.com]
Hello group,
This is kinda related with my earlier question about lumping
parameters. now that I have lumped my parameters, I would like to
define a new rule that reverses the lumping. I could od it manually,
but it just seem there should be a better way of doing it..
Suppose you have the following rule for replacing parameters. (in
lumping, I used up all the letters in alphabet and about half of
double struck letters. So the actual rule is very long.)
toyrule = {k1 k2 -> a, k3 k4 k5 -> b, k4 k6 k7 -> c, k8 k9/k10 + k11 -
> d }
and so on and on.
What I want to accomplish is now come up with reverse rule that with
replace the lumped parameter with primitive parameters.
revtoyrule = {a -> k1 k2, b -> k3 k4 k5 , c-> k4 k6 k7, d-> k8 k9/
k10 + k11}
And so on.
Thanks much in advance.
Sean