Re: Aspect Ratio
- To: mathgroup at smc.vnet.net
- Subject: [mg94996] Re: [mg94985] Aspect Ratio
- From: DrMajorBob <btreat1 at austin.rr.com>
- Date: Thu, 1 Jan 2009 21:51:59 -0500 (EST)
- References: <200901020129.UAA23788@smc.vnet.net>
- Reply-to: drmajorbob at longhorns.com
Here are two methods. The first depends on knowing precisely the structure of the Graphics object (not likely in practice). r1 = Graphics[Rectangle[{0, 0}, {1, 10}]]; r2 = Graphics[Rectangle[{0, 0}, {1, 2}]]; r1[[1, -1]] r2[[1, -1]] {1, 10} {1, 2} The second method doesn't have THAT flaw, but it could return coordinates from embedded rectangles OTHER than the one you want. (Depending on how you derived the object in the first place.) Cases[{r1, r2}, r_Rectangle :> Last@r, Infinity] {{1, 10}, {1, 2}} Bobby On Thu, 01 Jan 2009 19:29:08 -0600, Nathan Myhrvold <nathanm at intven.com> wrote: > Here is a simple question - is there a way to find out the aspect > ratio of a graphics object? > > So if I have > > r1 = Graphics[Rectangle[{0,0},{1,10}]] > r2 = Graphics[Rectangle[{0,0},{1,2}]] > > I want to recover {1,10} from r1, and {1,2} from r2. > > > Nathan > > This message and any attachments, may contain confidential and/or > legally privileged information. If you are not the intended recipient > of the message by the original sender, please destroy it. Message and > attachments copyright =A9 2008, all rights reserved. Any unauthorized > dissemination, distribution or copying is strictly forbidden > -- DrMajorBob at longhorns.com
- References:
- Aspect Ratio
- From: "Nathan Myhrvold" <nathanm@intven.com>
- Aspect Ratio