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Re: Azimuth in Mathematica

  • To: mathgroup at smc.vnet.net
  • Subject: [mg95086] Re: [mg95071] Azimuth in Mathematica
  • From: Curtis Osterhoudt <cfo at lanl.gov>
  • Date: Tue, 6 Jan 2009 04:09:49 -0500 (EST)
  • Organization: LANL
  • References: <200901050828.DAA20571@smc.vnet.net>
  • Reply-to: cfo at lanl.gov

Hi, TL, 

   Use the two-argument form of ArcTan:

ArcTan[z] gives the arc tangent tan^-1(z) of the complex number z. 
ArcTan[x,y] gives the arc tangent of y/x, taking into account which quadrant the point (x,y) is in. 

             Cheers, 
                           CO

On Monday 05 January 2009 01:28:32 TL wrote:
> Is there a function in Mathematica that would return the azimuth between 
> two points with known coordinates, 0 being North?
> For example having A(0,0), B(1,0) - the azimuth should be 90 degrees
> its like ArcTan[dx/dy], but I need the quadrant taken into account as 
> well and I need it to handle 90 and 270 degrees properly too
> 
> /it doesn't need to convert the angles to degrees, rads is ok/
> 
> 



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