Re: 0^0 = 1?

*To*: mathgroup at smc.vnet.net*Subject*: [mg95621] Re: 0^0 = 1?*From*: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>*Date*: Thu, 22 Jan 2009 07:15:23 -0500 (EST)*Organization*: Uni Leipzig*References*: <gl7211$c8r$1@smc.vnet.net>*Reply-to*: kuska at informatik.uni-leipzig.de

Hi, and Derive make a mistake, as expected. It is stuff from the elementary school that 0^0 is undefined because x^0 /; x!=0 is 1 but 0^x /; x!=0 is 0. Only if you have some sequences x[n] and y[n] with Limit[x[n],n->Infinity]==0 and Limit[y[n],n->Infinity]==0 you can take the limit Limit[x[n]^y[n],n->Infinity] and may get a defined result. Regards Jens ivflam at gmail.com wrote: > Mathematica says 0^0 = Indeterminate > Derive says 0^0 = 1 > > May I have any opinions? > > Bruno >