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Re: 0^0 = 1?


Hi,

and Derive make a mistake, as expected.
It is stuff from the elementary school
that 0^0 is undefined because
x^0 /; x!=0 is 1 but 0^x /; x!=0 is 0.
Only if you have
some sequences x[n] and y[n] with
Limit[x[n],n->Infinity]==0 and Limit[y[n],n->Infinity]==0
you can take the limit Limit[x[n]^y[n],n->Infinity]
and may get a defined result.

Regards
   Jens

ivflam at gmail.com wrote:
> Mathematica says 0^0 = Indeterminate
> Derive says 0^0 = 1
> 
> May I have any opinions?
> 
> Bruno
> 


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