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Re: Derivative

  • To: mathgroup at smc.vnet.net
  • Subject: [mg95877] Re: Derivative
  • From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
  • Date: Thu, 29 Jan 2009 05:53:03 -0500 (EST)
  • Organization: Uni Leipzig
  • References: <glpgeg$lin$1@smc.vnet.net>
  • Reply-to: kuska at informatik.uni-leipzig.de

Hi,

and what does

Derivative[1, 0, 0][Norton][arg_, n_, k_] := dNdx[arg, n, k]
Norton[arg_, exp_?NumericQ, nenner_?NumericQ] := MCB[arg/nenner]^exp

??

Mathematica evaluates Norton[] before it compute the derivative
and so you must hinder Mathematica to evaluate Norton[] with pure
symbolic arguments.

Regards
   Jens

Cetin Haftaoglu wrote:
> Dear Users,
> 
>  
> 
> I have a function 
> 
>  
> 
>                 Norton[arg_,exp_,nenner_]:= MCB[arg / nenner]^exp
> 
>  
> 
> I want to define my own deviation of the function Norton,
> D[Norton[arg,exp,nen],y[1]]:=dNdx[arg,exp,nen]
> 
> arg depends on y[1].
> 
> I have tried it with
> 
>  
> 
>                 Derivative[1,0,0][Norton][arg_,n_,k_]:=dNdx[arg,n,k]
> 
>  
> 
> But I get an error.
> 
>  
> 
> Thanks in advance.
> 
>  
> 
> Cetin Haftaoglu
> 


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