Re: Derivative
- To: mathgroup at smc.vnet.net
- Subject: [mg95877] Re: Derivative
- From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
- Date: Thu, 29 Jan 2009 05:53:03 -0500 (EST)
- Organization: Uni Leipzig
- References: <glpgeg$lin$1@smc.vnet.net>
- Reply-to: kuska at informatik.uni-leipzig.de
Hi, and what does Derivative[1, 0, 0][Norton][arg_, n_, k_] := dNdx[arg, n, k] Norton[arg_, exp_?NumericQ, nenner_?NumericQ] := MCB[arg/nenner]^exp ?? Mathematica evaluates Norton[] before it compute the derivative and so you must hinder Mathematica to evaluate Norton[] with pure symbolic arguments. Regards Jens Cetin Haftaoglu wrote: > Dear Users, > > > > I have a function > > > > Norton[arg_,exp_,nenner_]:= MCB[arg / nenner]^exp > > > > I want to define my own deviation of the function Norton, > D[Norton[arg,exp,nen],y[1]]:=dNdx[arg,exp,nen] > > arg depends on y[1]. > > I have tried it with > > > > Derivative[1,0,0][Norton][arg_,n_,k_]:=dNdx[arg,n,k] > > > > But I get an error. > > > > Thanks in advance. > > > > Cetin Haftaoglu >