Re: ListCurvePathPlot

*To*: mathgroup at smc.vnet.net*Subject*: [mg95931] Re: ListCurvePathPlot*From*: Bill Rowe <readnews at sbcglobal.net>*Date*: Fri, 30 Jan 2009 05:43:16 -0500 (EST)

On 1/29/09 at 5:58 AM, djmpark at comcast.net (David Park) wrote: >I don't understand the new ListCurvePathPlot, which the Help page >says: "attempts to reconstruct smooth curves defined by the >specified set of points." >This plot routine also has the option: InterpolationOrder. And the >word "Curve" appears not only in the name but repeatedly in the >descriptions. But look at the following example: >data = Table[ >RandomReal[{.8, 1.2}] {Cos[t], Sin[t]}, {t, 0, 2 \[Pi] - 2 \[Pi]/6, >2 \[Pi]/6}]; >ListCurvePathPlot[data,InterpolationOrder -> 3, >Axes -> False] >I don't see anything "smooth" or "curvy" about the results! I am not totally convinced this is a meaningful test example. So few data points really provide very little information about an underlying curve. However, there does seem to be a problem with InterpolationOrder. Contrast the plot you get with the plot resulting from LineListPlot[data, InterpolationOrder->3] Although the resulting curve is not closed, it now has a smooth appearance. As for your other questions, I don't know the answers and can only speculate.