Re: Different (real) solutions using Solve for same equation ?
- To: mathgroup at smc.vnet.net
- Subject: [mg101872] Re: Different (real) solutions using Solve for same equation ?
- From: Richard Fateman <fateman at cs.berkeley.edu>
- Date: Mon, 20 Jul 2009 06:02:00 -0400 (EDT)
- References: <email@example.com>
Bill Rowe wrote: >... > > That is the re-write you did implicitly assumes certain values > are not zero. Mathematica never makes such assumptions. Not in my experience. It makes such assumptions in many instances. The simplest one that comes to mind is this. Solve[(x-a)/(x-b)==0,x] produces x -->a. Using Reduce reminds you that a-b had better not be zero. So Solve assumes a-b is not zero. another: Integrate[x^n,x] assumes n+1 is not zero. Even the documentation says "Parameters like n are assumed to be generic inside indefinite integrals." RJF