Re: Re: differentiation operator
- To: mathgroup at smc.vnet.net
- Subject: [mg100719] Re: [mg100662] Re: differentiation operator
- From: Murray Eisenberg <murray at math.umass.edu>
- Date: Thu, 11 Jun 2009 21:43:06 -0400 (EDT)
- Organization: Mathematics & Statistics, Univ. of Mass./Amherst
- References: <h0nulh$be1$1@smc.vnet.net> <200906102110.RAA00562@smc.vnet.net>
- Reply-to: murray at math.umass.edu
That works reasonable well. For example, all the following forms work OK
(in the last form I simulate the Mathematica 2D standard form):
d/dx Sin[x]
(d/dx) Sin[x]
(d Sin[x])/dx
d
-- Sin[x]
dx
However, what does NOT work as one might hope is...
d Sin[x]/x
...even though that is a perfectly acceptable, traditional (with a small
"t") mathematical form for the same derivative.
Of course the use of the d/dx ties everything to a particular variable.
Change from x to y or t or something else, and it's dead.
dh wrote:
> Hi Chee,
>
> I did not thoroughly test it, but if you define:
>
> $Pre = # /. Times[ d expr_ Power[dx, -1]] :> D[expr, x] &
>
> the following examples work:
>
> d/dx x^2 -> 2x
>
> d/dx Sin[x] -> Cos[x]
>
> d/dx (x-x^3) -> 1-3x^2
>
> e.t.c
>
> Daniel
>
>
>
> Chee Lim Cheung wrote:
>
>> Hi All
>
>
>> My students have asked me whether it is possible to define the operator
>
>> df[x]/dx for differentiation rather than D[f[x],x]. The operator is
>
>> available in a palette but it does not seem to do anything other than for
>
>> display only.
>
>
>> Example: d/dx(x^2)=2x rather than D[x^2,x]=2x.
>
>
>> Am I missing something?
>
>
>> Thanks
>
>> Mr. Chee
>
>
>
>
--
Murray Eisenberg murray at math.umass.edu
Mathematics & Statistics Dept.
Lederle Graduate Research Tower phone 413 549-1020 (H)
University of Massachusetts 413 545-2859 (W)
710 North Pleasant Street fax 413 545-1801
Amherst, MA 01003-9305
- References:
- Re: differentiation operator
- From: dh <dh@metrohm.com>
- Re: differentiation operator