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Re: Hilbert transform bug in 7.0.3?

Hi Daniel.

You are right, without PrincipalValues, it works fine. I took the
definition from Mathworld directly, and it seems it works with the
PrincipalValues->True in previous versions.



On Jun 17, 10:33 am, dh <d... at> wrote:
> Hi Nacho,
> your problem comes from the fact that you are using PrincipalValue ->
> True together with DiracDelta. Consider the simplest case:
> Integrate[DiracDelta[x], {x, -Infinity, Infinity}]
> Integrate[DiracDelta[x], {x, -Infinity, Infinity},PrincipalValue -> True]
> The first integral gives 1 in agreement with the definition of
> DiracDelta. The second integral is actually a limit of two integrals.
> One from -Infinity to epsilon. The second from epsilon to Infinity. For
> epsilon > 0 both integrals are zero. Therefore, the limit is also zero.
> Daniel

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