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Re: For loops with mathematica....

  • To: mathgroup at smc.vnet.net
  • Subject: [mg101128] Re: [mg101069] For loops with mathematica....
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Wed, 24 Jun 2009 06:36:35 -0400 (EDT)
  • Reply-to: hanlonr at cox.net

Table[i^2, {i, Flatten[{Range[20, 200, 30], Range[300, 400, 25]}]}]

Do[y = i^2; Print[y]; 
 Print[i == Sqrt[y]], {i, 
  Flatten[{Range[20, 200, 30], Range[300, 400, 25]}]}]


Bob Hanlon

---- Julien <jderr at cgr.harvard.edu> wrote: 

=============
Hey guys, 

I am totally new to mathematica.
I want to use a simple loop for but with many arguments in the loop...
the help says to do

Do[ thingstodo, {i,8}]

i will go from 1 to 8 to do thingstodo.

First question: what if I want i to go from 20 then 200 then 300 then 400, (can we give a sequence as argument?)

Second question: I have a lot of line to do in things to do. should I separate everything with a ; (doesn t seem to work, or use a procedure or something?)


THanks a lot for your help!!!

Julien




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