Re: For loops with mathematica....

*To*: mathgroup at smc.vnet.net*Subject*: [mg101128] Re: [mg101069] For loops with mathematica....*From*: Bob Hanlon <hanlonr at cox.net>*Date*: Wed, 24 Jun 2009 06:36:35 -0400 (EDT)*Reply-to*: hanlonr at cox.net

Table[i^2, {i, Flatten[{Range[20, 200, 30], Range[300, 400, 25]}]}] Do[y = i^2; Print[y]; Print[i == Sqrt[y]], {i, Flatten[{Range[20, 200, 30], Range[300, 400, 25]}]}] Bob Hanlon ---- Julien <jderr at cgr.harvard.edu> wrote: ============= Hey guys, I am totally new to mathematica. I want to use a simple loop for but with many arguments in the loop... the help says to do Do[ thingstodo, {i,8}] i will go from 1 to 8 to do thingstodo. First question: what if I want i to go from 20 then 200 then 300 then 400, (can we give a sequence as argument?) Second question: I have a lot of line to do in things to do. should I separate everything with a ; (doesn t seem to work, or use a procedure or something?) THanks a lot for your help!!! Julien