Re: For loops with mathematica....

*To*: mathgroup at smc.vnet.net*Subject*: [mg101102] Re: [mg101069] For loops with mathematica....*From*: Julien Derr <jderr at cgr.harvard.edu>*Date*: Wed, 24 Jun 2009 06:31:46 -0400 (EDT)*References*: <20090623082433.ZRWPU.18126.imail@eastrmwml28>

Thank you so much everyone for all the interesting/very helpful comments!!! Julien On Jun 23, 2009, at 8:24 AM, Bob Hanlon wrote: > > Table[i^2, {i, Flatten[{Range[20, 200, 30], Range[300, 400, 25]}]}] > > Do[y = i^2; Print[y]; > Print[i == Sqrt[y]], {i, > Flatten[{Range[20, 200, 30], Range[300, 400, 25]}]}] > > > Bob Hanlon > > ---- Julien <jderr at cgr.harvard.edu> wrote: > > ============= > Hey guys, > > I am totally new to mathematica. > I want to use a simple loop for but with many arguments in the loop... > the help says to do > > Do[ thingstodo, {i,8}] > > i will go from 1 to 8 to do thingstodo. > > First question: what if I want i to go from 20 then 200 then 300 > then 400, (can we give a sequence as argument?) > > Second question: I have a lot of line to do in things to do. should > I separate everything with a ; (doesn t seem to work, or use a > procedure or something?) > > > THanks a lot for your help!!! > > Julien > >