Re: Inverse function

*To*: mathgroup at smc.vnet.net*Subject*: [mg99329] Re: [mg99301] Inverse function*From*: DrMajorBob <btreat1 at austin.rr.com>*Date*: Sun, 3 May 2009 05:19:45 -0400 (EDT)*References*: <200905020959.FAA15364@smc.vnet.net>*Reply-to*: drmajorbob at bigfoot.com

invFunction[y_] = x /. First@Solve[y == 5/(2 - x), x] (-5 + 2 y)/y Bobby On Sat, 02 May 2009 04:59:08 -0500, davef <davidfrick2003 at yahoo.com> wrote: > I have two questions: > > 1. Is it possible to find the inveses function for one-to-one function > in Mathematica 7? > > For example the inverse of 5/(2-x) is 2-(5/x). I have tried Inverse and > InverseFunction but I cannot produce the inverse function. > > Can anyone explain how to get Mathematica to produce this result? (See > attached output screenshot.) > > > 2. Is it possible to change the format of the output for a recprical? > > For example, instead of writing the output of Inverse[5/(2-x)] as > (5/(2-x))^-1, can the output be set to produce (2-x)/5? > -- DrMajorBob at bigfoot.com

**References**:**Inverse function***From:*davef <davidfrick2003@yahoo.com>