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Re: Inverse function

  • To: mathgroup at smc.vnet.net
  • Subject: [mg99329] Re: [mg99301] Inverse function
  • From: DrMajorBob <btreat1 at austin.rr.com>
  • Date: Sun, 3 May 2009 05:19:45 -0400 (EDT)
  • References: <200905020959.FAA15364@smc.vnet.net>
  • Reply-to: drmajorbob at bigfoot.com

invFunction[y_] = x /. First@Solve[y == 5/(2 - x), x]

(-5 + 2 y)/y

Bobby

On Sat, 02 May 2009 04:59:08 -0500, davef <davidfrick2003 at yahoo.com> wrote:

> I have two questions:
>
> 1. Is it possible to find the inveses function for one-to-one function  
> in Mathematica 7?
>
> For example the inverse of 5/(2-x) is 2-(5/x). I have tried Inverse and  
> InverseFunction but I cannot produce the inverse function.
>
> Can anyone explain how to get Mathematica to produce this result? (See  
> attached output screenshot.)
>
>
> 2. Is it possible to change the format of the output for a recprical?
>
> For example, instead of writing the output of Inverse[5/(2-x)] as  
> (5/(2-x))^-1, can the output be set to produce (2-x)/5?
>



-- 
DrMajorBob at bigfoot.com


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