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Re: Some function like Position[] but uses criteria, not

  • To: mathgroup at smc.vnet.net
  • Subject: [mg99460] Re: [mg99389] Some function like Position[] but uses criteria, not
  • From: DrMajorBob <btreat1 at austin.rr.com>
  • Date: Wed, 6 May 2009 05:23:44 -0400 (EDT)
  • References: <200905050937.FAA20364@smc.vnet.net>
  • Reply-to: drmajorbob at bigfoot.com

a = {1, 0, 4, -5, 8};
Position[a, _?(Positive[# - 3] &)]
Position[a, x_ /; x > 3]

{{3}, {5}}

{{3}, {5}}

Bobby

On Tue, 05 May 2009 04:37:22 -0500, Nasser Abbasi <nma at 12000.org> wrote:

> V 7.0
>
> Position[]  works by returning position of elements which matches a  
> pattern.
> This is all good and well.
>
> But sometimes, I need to find the positions (i.e index) of elements that
> matches a criteria, not a pattern.
>
> For example, using pattern
>
> a = {1, 0, 4, -5, 8}
> Position[a, 0]
> Out[15]= {{2}}
>
> But what if I wanted the position of the elements which, say, are larger
> than 3? this is not a pttern, but a criteria. Which in this example  
> should
> find elements which are in position 3 and 5 in list 'a' above.
>
> I can't type
> Position[a, #1 > 3 & ]
>
> Now, Select[] does take a criteria, good, so I could type
>
> Select[a, #1 > 3 & ]
> {4, 8}
>
> But I wanted the positions of the elements, not the elements themselves.
>
> I could use Select to find the elements, then use Position to find the
> position of these elements as follows
>
> c = Select[a, #1 > 3 & ];
> Flatten[(Position[a, #1] & ) /@ c]
>
> Out[65]= {3, 5}
>
> But I think this is bit messy. I think Position[] or new function  
> similar,
> should have an option to return position of elements based on criteria,  
> not
> just pattern. The above gets more messy for me, when I wanted to find
> position of elements in a matrix based on some criteria.
>
> For example, find the position (i.e. row and column) index in a matrix  
> (list
> of lists) of those elements which matches some criteria. Say >3.
>
> thanks,
> --Nasser
>
>
>
>



-- 
DrMajorBob at bigfoot.com


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