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Re: Some function like Position[] but uses criteria, not pattern?
*To*: mathgroup at smc.vnet.net
*Subject*: [mg99467] Re: [mg99389] Some function like Position[] but uses criteria, not pattern?
*From*: Curtis Osterhoudt <cfo at lanl.gov>
*Date*: Wed, 6 May 2009 05:25:03 -0400 (EDT)
*Organization*: LANL
*References*: <200905050937.FAA20364@smc.vnet.net>
*Reply-to*: cfo at lanl.gov
In[1]:= a = {1, 0, 4, -5, 8}
Out[1]= {1, 0, 4, -5, 8}
In[2]:= Position[a, 0]
Out[2]= {{2}}
In[4]:= Position[a, _?(# > 3 &)]
Out[4]= {{3}, {5}}
Hope that helps,
C.O.
On Tuesday 05 May 2009 03:37:22 am Nasser Abbasi wrote:
> V 7.0
>
> Position[] works by returning position of elements which matches a pattern.
> This is all good and well.
>
> But sometimes, I need to find the positions (i.e index) of elements that
> matches a criteria, not a pattern.
>
> For example, using pattern
>
> a = {1, 0, 4, -5, 8}
> Position[a, 0]
> Out[15]= {{2}}
>
> But what if I wanted the position of the elements which, say, are larger
> than 3? this is not a pttern, but a criteria. Which in this example should
> find elements which are in position 3 and 5 in list 'a' above.
>
> I can't type
> Position[a, #1 > 3 & ]
>
> Now, Select[] does take a criteria, good, so I could type
>
> Select[a, #1 > 3 & ]
> {4, 8}
>
> But I wanted the positions of the elements, not the elements themselves.
>
> I could use Select to find the elements, then use Position to find the
> position of these elements as follows
>
> c = Select[a, #1 > 3 & ];
> Flatten[(Position[a, #1] & ) /@ c]
>
> Out[65]= {3, 5}
>
> But I think this is bit messy. I think Position[] or new function similar,
> should have an option to return position of elements based on criteria, not
> just pattern. The above gets more messy for me, when I wanted to find
> position of elements in a matrix based on some criteria.
>
> For example, find the position (i.e. row and column) index in a matrix (list
> of lists) of those elements which matches some criteria. Say >3.
>
> thanks,
> --Nasser
>
>
>
>
>
--
==================================
Curtis Osterhoudt
cfo at remove_this.lanl.and_this.gov
PGP Key ID: 0x4DCA2A10
==================================
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