Re: volume calculation

*To*: mathgroup at smc.vnet.net*Subject*: [mg100243] Re: [mg100240] volume calculation*From*: Leonid Shifrin <lshifr at gmail.com>*Date*: Fri, 29 May 2009 20:56:54 -0400 (EDT)*References*: <200905282335.TAA15300@smc.vnet.net>

Hi, I would just use NIntegrate[Boole[D(x1,x2,x3,...,xn) < L],{whatever your limits in xi}]. possibly with a Monte-Carlo method. If integration limits in coordinates depend on other coordinates in a way that is hard to disentangle, I would find the minimal multidimensional "box" with fixed dimensions that contains your domain, and integrate over that box. Regards, Leonid On Thu, May 28, 2009 at 4:35 PM, Filippo Miatto <miatto at gmail.com> wrote: > Dear all, > I need a way to find the volume of a multidimensional shape in the > coordinates (x1,x2,x3,...,xn), that comes from an inequality like > D(x1,x2,x3,...,xn) < L (with 3 variables i get a nice weird shape in > R^3, with more i don't plot it) > In other words I let Mathematica calculate where in the space of the > solutions the inequality is solved and i'd like to have the numerical > "volume of the solutions". > What strategy should i use? The function D is not invertible... > Thank you, > Filippo > > > > ------------------------------------------------------------ > Mobile (IT): +39 340 6104269 > Mobile (NL): +31 064 3949827 > Home (IT): +39 0438 59360 > > P.O. Box 9504 > NL 2300 RA LEIDEN > > msn: dr.ziofil at hotmail.com > skype: filippo.miatto > Quantum Optics > Group Mail: miatto at molphys.leidenuniv.nl >

**Follow-Ups**:**Re: Re: volume calculation***From:*Filippo Miatto <miatto@gmail.com>

**References**:**volume calculation***From:*Filippo Miatto <miatto@gmail.com>