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Re: Answer for Simplify[Cos[x]^4-Sin[x]^4]?
On 10/30/09 at 2:19 AM, lawrenceteo at yahoo.com (Lawrence Teo) wrote: >We know that Simplify[Cos[x]^2-Sin[x]^2] -> Cos[2 x] But why >Simplify[Cos[x]^4-Sin[x]^4] -> Cos[2 x] too? >Doing subtraction between the two expressions will give small delta. >This is enough to prove that the two expression shouldn't be the >same. When you did the subtraction did you do: In:= Cos[x]^2 - Sin[x]^2 - (Cos[x]^4 - Sin[x]^4) // Simplify Out= 0 which is correct. Or did you fail to include the parentheses and do In:= Cos[x]^2 - Sin[x]^2 - Cos[x]^4 - Sin[x]^4 // Simplify Out= -2 sin^4(x) Since, this result could be characterized as a "small delta", my guess is this is what you did. But this is not the difference between the two expressions.