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Re: Define a function as a graphics directive?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg105066] Re: Define a function as a graphics directive?
  • From: Harrie Kraai <hakraai at xs4all.nl>
  • Date: Thu, 19 Nov 2009 07:25:05 -0500 (EST)
  • References: <he0ngh$43r$1@smc.vnet.net>

Hi,

My quick solution would be this:

cpl = ContourPlot[
   z Exp[-Sqrt[z^2 + x^2]/2.], {x, -10, 10}, {z, -10, 10},
   ContourShading -> None, Contours -> 15, ContourStyle -> {Thick}];

cpl /. {tt_Tooltip :> Sequence[If[tt[[2]] > 0, Black, Red], tt]}

which makes use of the fact that the tooltip contains the value of the 
contourline

Have fun,

HK


Porscha Louise McRobbie wrote:
> Hi,
> 
> I have a very simple contour plot:
> 
> 
> ContourPlot[ z Exp[-Sqrt[z^2 + x^2]/2.], {x, -10, 10}, {z, -10, 10},
>   ContourShading -> None, Contours -> 15,
>   ContourStyle -> {{Black, Thick}}]
> 
> 
> I do not want the plot shaded, but I want to color the contour lines  
> according to  a function of z (e.g., Sign[z], where z>0 is black, z<0  
> is red). Can this be done within ContourStyle?
> 
> I tried putting a function definition for the color inside  
> ContourShading, but I get an error since it's not a graphics directive  
> (and it's my understanding that ColorFunction is only for shading the  
> regions between contours).
> 
> Thanks for any input!
> Porscha
> 
> 
> 
> 
> 


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