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Re: on passing arguments to a function, how to break a list into

  • To: mathgroup at smc.vnet.net
  • Subject: [mg103740] Re: on passing arguments to a function, how to break a list into
  • From: Albert Retey <awnl at gmx-topmail.de>
  • Date: Sun, 4 Oct 2009 05:37:06 -0400 (EDT)
  • References: <ha7hvj$5qe$1@smc.vnet.net>

Hi,

> Suppose there is a function foo[] which returns back 2 items, say 'i' and 
> 'j'. They must be returned as a list ofcourse, so we have this
> 
> foo[] := Module[{i, j},
>      i = 3;
>      j = 7;
>     {i, j}
> ]
> 
> Now I have another function goo[] which accepts 2 items as input, and does 
> something with them, as in
> 
> goo[i_, j_] := Module[{},
>          i + j
> ]
> 
> Now I'd like to call foo[], and take its output, and pass it to directly to 
> goo[], but I can NOT do the following:
> 
>                              goo[foo[]]

Everything you need is already there (of course :-)). This will do the
trick:

goo@@foo[]

or

Apply[goo,foo[]]

another thing you might want to look at is Sequence, I use it often in
combination with Apply, e.g. if a function goo3 wants three arguments
you could do something like:

goo3[1,Sequence@@foo[]]

hth,

albert


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