Re: Better Way of Testing and Replacing List Elements?
- To: mathgroup at smc.vnet.net
- Subject: [mg103992] Re: [mg103949] Better Way of Testing and Replacing List Elements?
- From: "Richard Hofler" <rhofler at bus.ucf.edu>
- Date: Wed, 14 Oct 2009 08:05:55 -0400 (EDT)
- References: <200910140319.XAA22469@smc.vnet.net>
Hello, I'm betting that you'll see many ways to do this. So, here's one: In[21]:= lst={1,2,3,4,5,-6,-7,8,9,10,-1,11,12}; Replace[lst,x_/;Negative[x]->0,1] Out[22]= {1,2,3,4,5,0,0,8,9,10,0,11,12} Richard Hofler ________________________________ From: careysub [mailto:careysub at gmail.com] Sent: Tue 10/13/2009 11:19 PM To: mathgroup at smc.vnet.net Subject: [mg103992] [mg103949] Better Way of Testing and Replacing List Elements? The code below replaces the negative values in a list with zero, and is an example of a type of operation I use a lot: xxx = {1, 2, 3, 4, 5, -6, -7, 8, 9, 10, -1, 11, 12}; ReplacePart[xxx, Position[Map[Negative, xxx], True] -> 0] Is there a "better" way of doing this (fewer function calls, more efficient)? My feeling is that I'm doing this in an awkward way.
- References:
- Better Way of Testing and Replacing List Elements?
- From: careysub <careysub@gmail.com>
- Better Way of Testing and Replacing List Elements?