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Re: (1234*(2/3)^(Log[1234]/Log[3])) === (1234^(Log[2]/Log[3])) should


On 19 Okt., 13:07, Luka Rahne <luka.ra... at gmail.com> wrote:
> what should be result of this evaluation?
>
> (1234*(2/3)^(Log[1234]/Log[3])) === (1234^(Log[2]/Log[3]))
>
> subqestion.
>
> How to make this work?

Here are 3 possibilities:

lhs = 1234*(2/3)^(Log[1234]/Log[3]);
rhs = 1234^(Log[2]/Log[3]);

N[lhs == rhs]
Simplify[lhs == rhs]

{lhs, rhs} = {lhs, rhs} /. {x : Log[_] :> x, x_?Positive :> E^Log[x]};
lhs === rhs

Best regards,
Hannes


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