Re: (1234*(2/3)^(Log[1234]/Log[3])) === (1234^(Log[2]/Log[3])) should

*To*: mathgroup at smc.vnet.net*Subject*: [mg104132] Re: (1234*(2/3)^(Log[1234]/Log[3])) === (1234^(Log[2]/Log[3])) should*From*: Hannes Kessler <HannesKessler at hushmail.com>*Date*: Tue, 20 Oct 2009 04:53:37 -0400 (EDT)*References*: <hbhha4$1s7$1@smc.vnet.net>

On 19 Okt., 13:07, Luka Rahne <luka.ra... at gmail.com> wrote: > what should be result of this evaluation? > > (1234*(2/3)^(Log[1234]/Log[3])) === (1234^(Log[2]/Log[3])) > > subqestion. > > How to make this work? Here are 3 possibilities: lhs = 1234*(2/3)^(Log[1234]/Log[3]); rhs = 1234^(Log[2]/Log[3]); N[lhs == rhs] Simplify[lhs == rhs] {lhs, rhs} = {lhs, rhs} /. {x : Log[_] :> x, x_?Positive :> E^Log[x]}; lhs === rhs Best regards, Hannes