Re: ReplaceAll and rules from a list v7.0
- To: mathgroup at smc.vnet.net
- Subject: [mg104291] Re: [mg104227] ReplaceAll and rules from a list v7.0
- From: Matthias Greiff <greiff at mac.com>
- Date: Sun, 25 Oct 2009 23:25:47 -0500 (EST)
- References: <200910240640.CAA07557@smc.vnet.net>
Kristoph, you can define the function and then use the Map-command: x[{a_, b_}] := a + b l = {{1, 1}, {2, 2}, {3, 3}} x /@ l or x[{a_, b_}] := a + b l = {{1, 1}, {2, 2}, {3, 3}} Map[x, l] This gives you {2,4,6}. Best, Matthias Am 24.10.2009 um 24. Oktober , 08:40:20 schrieb kristoph: > Hi, > > Suppose I have the equation > > x=a+b > > and the list > > l={{1,1},{2,2},{3,3}} > > How can I quickly assign the list to the above equation, that is, I > would like to get the following result > > {2,4,6} > > The first element of each sub-list should be assigned to a and the > second to b. > > Thanks in advance. > Kristoph >
- References:
- ReplaceAll and rules from a list v7.0
- From: kristoph <kristophs.post@web.de>
- ReplaceAll and rules from a list v7.0