Re: ReplaceAll and rules from a list v7.0

*To*: mathgroup at smc.vnet.net*Subject*: [mg104291] Re: [mg104227] ReplaceAll and rules from a list v7.0*From*: Matthias Greiff <greiff at mac.com>*Date*: Sun, 25 Oct 2009 23:25:47 -0500 (EST)*References*: <200910240640.CAA07557@smc.vnet.net>

Kristoph, you can define the function and then use the Map-command: x[{a_, b_}] := a + b l = {{1, 1}, {2, 2}, {3, 3}} x /@ l or x[{a_, b_}] := a + b l = {{1, 1}, {2, 2}, {3, 3}} Map[x, l] This gives you {2,4,6}. Best, Matthias Am 24.10.2009 um 24. Oktober , 08:40:20 schrieb kristoph: > Hi, > > Suppose I have the equation > > x=a+b > > and the list > > l={{1,1},{2,2},{3,3}} > > How can I quickly assign the list to the above equation, that is, I > would like to get the following result > > {2,4,6} > > The first element of each sub-list should be assigned to a and the > second to b. > > Thanks in advance. > Kristoph >

**References**:**ReplaceAll and rules from a list v7.0***From:*kristoph <kristophs.post@web.de>