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Re: ReplaceAll and rules from a list v7.0


Kristoph,
you can define the function and then use the Map-command:

x[{a_, b_}] := a + b
l = {{1, 1}, {2, 2}, {3, 3}}
x /@ l

or

x[{a_, b_}] := a + b
l = {{1, 1}, {2, 2}, {3, 3}}
Map[x, l]

This gives you {2,4,6}.

Best,

Matthias

Am 24.10.2009 um 24. Oktober , 08:40:20 schrieb kristoph:

> Hi,
>
> Suppose I have the equation
>
> x=a+b
>
> and the list
>
> l={{1,1},{2,2},{3,3}}
>
> How can I quickly assign the list to the above equation, that is, I
> would like to get the following result
>
> {2,4,6}
>
> The first element of each sub-list should be assigned to a and the
> second to b.
>
> Thanks in advance.
> Kristoph
>



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