Re: ReplaceAll and rules from a list v7.0

*To*: mathgroup at smc.vnet.net*Subject*: [mg104382] Re: ReplaceAll and rules from a list v7.0*From*: kristoph <kristophs.post at web.de>*Date*: Thu, 29 Oct 2009 03:00:23 -0500 (EST)*References*: <200910240640.CAA07557@smc.vnet.net> <hc38dt$i6c$1@smc.vnet.net>

On 26 Okt., 05:26, Matthias Greiff <gre... at mac.com> wrote: > Kristoph, > you can define the function and then use the Map-command: > > x[{a_, b_}] := a + b > l = {{1, 1}, {2, 2}, {3, 3}} > x /@ l > > or > > x[{a_, b_}] := a + b > l = {{1, 1}, {2, 2}, {3, 3}} > Map[x, l] > > This gives you {2,4,6}. > > Best, > > Matthias > > Am 24.10.2009 um 24. Oktober , 08:40:20 schrieb kristoph: > > > Hi, > > > Suppose I have the equation > > > x=a+b > > > and the list > > > l={{1,1},{2,2},{3,3}} > > > How can I quickly assign the list to the above equation, that is, I > > would like to get the following result > > > {2,4,6} > > > The first element of each sub-list should be assigned to a and the > > second to b. > > > Thanks in advance. > > Kristoph Thanks for all the great answers. Kristoph

**References**:**ReplaceAll and rules from a list v7.0***From:*kristoph <kristophs.post@web.de>