Re: Equations over Domains with Mathematica 4?
- To: mathgroup at smc.vnet.net
- Subject: [mg103080] Re: [mg103065] Equations over Domains with Mathematica 4?
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Mon, 7 Sep 2009 02:36:00 -0400 (EDT)
- Reply-to: hanlonr at cox.net
I don't have v4 on my machine but this should work
soln = Reduce[13219.56 == 20000/1.95583*(1 + z)^11, z];
Select[soln, FreeQ[#, Complex] &]
z\[LongEqual]0.0236182
% // ToRules
{z->0.0236182}
Bob Hanlon
---- Martin Harborth <martin.harborth at yahoo.de> wrote:
=============
For the following equation, I want to get only the solutions
for z where z is real:
Reduce[13219.56 == 20000/1.95583 * (1 + z)^11, z]
It is suggested that one uses
Reduce[13219.56 == 20000/1.95583 * (1 + z)^11, z, Reals]
But I use Mathematica 4 and it seems that Reduce does not have
this option in this Mathematica version.
Can I anyway constrain the solution space with Mathematica 4?
Thanks in advance
M. Harborth.